Describe how to transform: (6radicalX^5)^7into an expression with a rational exponent. Make sure yourespond with complete sentences. (10 points)I’ll vote you Brainliest :)

Answer:[tex]x^\frac{35}{6}[/tex]Step-by-step explanation:The expression to transform is:[tex](\sqrt[6]{x^5})^7[/tex]Let's work first on the inside of the parenthesis.Recall that the n-root of an expression can be written as a fractional exponent of the expression as follows:[tex]\sqrt[n]{a} = a^{\frac{1}{n}}[/tex]Therefore [tex]\sqrt[6]{a} = a^{\frac{1}{6}}[/tex]Now let's replace [tex]a[/tex] with [tex]x^{5}[/tex] which is the algebraic form we are given inside the 6th root:[tex]\sqrt[6]{x^5} = (x^5)^{\frac{1}{6}}[/tex]Now use the property that tells us how to proceed when we have  "exponent of an exponent":[tex](a^n)^m= a^{n*m}[/tex]Therefore we get:  [tex](x^5)^{\frac{1}{6}}=x^{\frac{5}{6}}}[/tex]Finally remember that this expression was raised to the power 7, therefore:[tex][tex](\sqrt[6]{x^5})^7=(x^\frac{5}{6})^7=x^\frac{35}{6}[/tex][/tex]An use again the property for the exponent of a exponent: