Hi! I'm not sure of the answer to this. Write the equation of a line that is perpendicular to the given line and passes through the given point y-2= 7/3 (x+5) ; (-5,2)Answer options:y+2= -3/7 (x-5)y-5= - 3/7 (x+2)y-2= -3/7 (x+5)y+2=3/7 (x-5)

Answer:y - 2 = (-3/7)(x + 5)Step-by-step explanation:Recall that the slopes of a line and another line perpendicular to the first are negative reciprocals.The slope of the given line is 7/3.  The negative reciprocal of that is -3/7.  Thus, we immediately eliminate the fourth answer choice.We must now find the equation of the perpendicular line, with slope -3/7, that passes through (-5, 2).  We'll do that using the point-slope formula for the equation of a straight line.That formula is    y - k = m(x - h), where m is the slope and (h, k) is the given point.Substituting 2 for k, -5 for h and -3/7 for m, we get:y - 2 = (-3/7)(x + 5).  This matches the 3rd given possible answer.