MATH SOLVE

2 months ago

Q:
# The length of a rectangle is six times it’s width if the area of the rectangle is 600m2 find its perimeter

Accepted Solution

A:

L = 6W

Area A = LW = 600. So, 6W(W) = 600, W2 = 600/6 = 100, so W = 10. Then L = 600/10 = 60.

Perimeter P = 2L + 2W = 2(60) + 2(10) = 120 + 20 = 140.

Area A = LW = 600. So, 6W(W) = 600, W2 = 600/6 = 100, so W = 10. Then L = 600/10 = 60.

Perimeter P = 2L + 2W = 2(60) + 2(10) = 120 + 20 = 140.